Squarring the Circle

Author:
RV'SMath
Square of a Circle - Adjust X and Y values with X=Y to get area of Circle. ( The x and y values are the radius of the Circle ) See Green equation and Compare to Radius and Hypotenuse -- Check the Numbers -- It should work; even if you cube or change the exponents. X=4,Y=4, x^n=.5, y^n=.5 is an interesting setting. 1) Input Box x and y (Blue) input boxes are the radius of each circle ( please read the therom below which states the problem ) 2) Input Box Exponents (Red) x^n and y^n can be adjusted. ( Mostly, to see the squaring, you should probably leave the exponents at 2 ) 3) Scale - Leave Scale at value - .7071 4) The Hypotenuse (Green) is the actual Length of the Hypotenuse of the Triangle made from the x and y values - which are the radius of the Circles - which, their(radius) "square areas" are equal to the Areas of the Circles made from these radius