Ambiguous Case for Areas of Triangles
- Author:
- liklikdy
This applet illustrates the ambiguous case in dealing with the area of a triangle calculated using A=(a*b*sin C)/2. By moving Point C around, the triangle on the right has the same area as the triangle on the left, but the included angle is the supplement of the one on the left.
The areas at the top remain identical for both triangles.