Eighth Circle Theorem: 'Perpendicular bisects the chord'
Eighth circle theorem: 'Perpendicular bisects the chord'
[this is a test version - I want to put a number of Circle Theorem ggb pages here, & am finding out how it all works!!]
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Perpendicular & chord
Perpendicular from the centre ,A, cutting a chord of the circle.
CD is the chord, and AE is perpendicular to it.
Move C or D, and note the connection between lengths CE and DE.
If you want to alter the size of the circle, move A or B.