# 1.3b-Activity4-Group1

- Author:
- James

To solve the inequality x^3+28x<10x^2+24, we first need to graph each side of the inequality in our calculators.
x^3+28x<y
y<10x^2+24
Then we will find any critical points of the inequality by finding the points of intersection between these two graphs.
x=2
x=6
Since x=2 and x=6 are both critical values of the inequality, we need to pick three test points - one to the left of x=2, one to the right of x=6, and one in-between x=2 and x=6. The test point(s) that gives a "true" statement when we plug in to the inequality is the correct side to shade on.