# lim [(sin x)/ x] as x ->0

Author:
gbattaly
Topic:
Limits
This demonstrates the squeeze theorem for determining the limit of [(sin x)/x] as x approaches 0. Click on point C on the upper part of the circle, and drag the point to varying positions. Watch the algebra window at the left for the areas of the Inner triangle (poly1), the sector (Sector), and the Outer triangle (poly2). Compare the areas. Then check the Limit (in pink) for the value of [(sin x) / x ].
What is the lim [(sinx) / x] ? x-->0 www.battaly.com/calc/