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已知橢圓 x^2/a^2+y^2/b^2=1 (a>b>0)
Author:
dunst_1
已知橢圓 x^2/a^2+y^2/b^2=1 (a>b>0) 與直線 x+y-1=0 交於 M,N 兩點 且 OM 垂直ON O 為原點 試證明此橢圓必過某一定點 for all a>b>0
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兩組對邊相等的四邊形
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