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Exercise 2.17 - Perpendicular from a point on the line (with rusty compass)
Auteur :
Gianluca Occhetta
5 circles + 1 line = 6 steps (par 6)
GeoGebra
The triangle CBF is equilateral by Construction 2.16, hence the triangles CAF and BAF are congruent by (I.8)
Nouvelles ressources
Midpoint Theorem (V2): Integer Solutions
Modifiable Right Triangular Prism
Function art 3D - waiting shed
Rovnoběžnost rovin
繪畫垂直線
Découvrir des ressources
Two-column proof (Corresponding Angles)
Argand Demo
Geogebra tutorial: line design complete
Ceva's Theorem
Modul 15.A2. Simpangan rata-rata_Trisdyanto_SMPN1 Bungoro
Découvrir des Thèmes
Pente
Carré
Courbes Paramétriques
Triangles Isocèles
Nuage de Points