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Exercise 2.17 - Perpendicular from a point on the line (with rusty compass)
Author:
Gianluca Occhetta
5 circles + 1 line = 6 steps (par 6)
GeoGebra
The triangle CBF is equilateral by Construction 2.16, hence the triangles CAF and BAF are congruent by (I.8)
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bewijs stelling van Pythagoras
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