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Exercise 2.17 - Perpendicular from a point on the line (with rusty compass)
Autor:
Gianluca Occhetta
5 circles + 1 line = 6 steps (par 6)
GeoGebra
The triangle CBF is equilateral by Construction 2.16, hence the triangles CAF and BAF are congruent by (I.8)
Nuevos recursos
Odd Function Explorer
What Do You See?
Congruent Figures
Quadrant Illustrator
繪畫垂直線
Descubrir recursos
Actividad #2 e)
Perpendicular Bisectors and the Circumcenter
Circle Definitions
Tan Curve
Definition of Derivative
Descubre temas
Problemas de Optimización
Rectángulo
Cálculo diferencial
Números Naturales
Triángulos Semejantes